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5b^2-11b-1=-3
We move all terms to the left:
5b^2-11b-1-(-3)=0
We add all the numbers together, and all the variables
5b^2-11b+2=0
a = 5; b = -11; c = +2;
Δ = b2-4ac
Δ = -112-4·5·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-9}{2*5}=\frac{2}{10} =1/5 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+9}{2*5}=\frac{20}{10} =2 $
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